18x-3x^2/2=0

Solution for 18x-3x^2/2=0 equation:

18x-3x^2/2=0

We multiply all the terms by the denominator


-3x^2+18x*2=0

Wy multiply elements

-3x^2+36x=0

a = -3; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-3)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-3}=\frac{-72}{-6}
=+12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-3}=\frac{0}{-6}
=0
$